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7x+47+x^2-92+10+1+9x-1+3x+48+163-3x+51+20x-x^2+2x^2-327=360
We move all terms to the left:
7x+47+x^2-92+10+1+9x-1+3x+48+163-3x+51+20x-x^2+2x^2-327-(360)=0
We add all the numbers together, and all the variables
2x^2+36x-460=0
a = 2; b = 36; c = -460;
Δ = b2-4ac
Δ = 362-4·2·(-460)
Δ = 4976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4976}=\sqrt{16*311}=\sqrt{16}*\sqrt{311}=4\sqrt{311}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{311}}{2*2}=\frac{-36-4\sqrt{311}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{311}}{2*2}=\frac{-36+4\sqrt{311}}{4} $
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